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SLIBMathematics

Mathematics: Applications and Interpretation

The Standard Level pathway applies mathematical models through statistics, functions, geometry, and calculus in real-world contexts.

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5

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Course Overview

IB Mathematics: Applications and Interpretation SL is organized into 5 units and 39 focused topics with 629 Key Concepts sections, 558 questions, and 780 flashcards.

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Begin with Topic 1.1: Scientific notation and operations with numbers.

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Course units

Each unit groups focused topics. Every topic follows the same clear rhythm: review Key Concepts, use the Question Bank, then strengthen recall.

  1. Unit 1
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    Number and Algebra

    Number and Algebra provides the quantitative tools used in finance, modelling and technology-supported problem solving. AI SL adds approximation, financial technology, annuities and numerical equation solving to the shared IB mathematics foundations of scientific notation, sequences and logarithms.

    8 topics

    Unit 1 progress0%

    Topics in this unit

    Topic 1.1Not started

    Scientific notation and operations with numbers

    Scientific notation represents extremely large and small quantities compactly. This AI SL lesson develops accurate operations, significant-figure decisions, calculator fluency and interpretation in authentic scientific, financial and technological contexts.

    180 min estimated

    Topic 1.1 progress0%
    Learning objectives
    • Recognize and write normalized scientific notation a×10ka\times10^k, where 1≤∣a∣<101\le |a|<10 and k∈Zk\in\mathbb Z.
    • Convert large and small quantities between ordinary notation and scientific notation.
    • Explain how positive, zero and negative powers of ten affect place value and scale.
    • Compare quantities and interpret their relative size or order of magnitude.
    • Multiply and divide quantities in scientific notation, then normalize the result.
    • Add and subtract quantities by first expressing them with a common power of ten.
    • Apply powers to numbers in scientific notation using the laws of indices.
    • Round values to a stated number of significant figures and preserve guard digits in multi-step work.
    • Enter, read and check scientific notation correctly on a calculator or GDC.
    • Replace calculator E-notation with conventional mathematical notation in final written answers.
    • Use scientific notation with units in scientific, financial and technological applications.
    • Judge whether an answer is reasonable by checking its sign, units, coefficient and exponent.
    Key formulas

    Normalized scientific notation

    N=a×10k,1≤∣a∣<10,k∈ZN=a\times10^k,\quad 1\le |a|<10,\quad k\in\mathbb Z

    Product of powers of ten

    10m×10n=10m+n10^m\times10^n=10^{m+n}

    Quotient of powers of ten

    10m10n=10m−n\frac{10^m}{10^n}=10^{m-n}

    Power of a power

    (10m)r=10mr(10^m)^r=10^{mr}

    Relative-size ratio

    factor=larger quantitysmaller quantity\text{factor}=\frac{\text{larger quantity}}{\text{smaller quantity}}

    Multiplication rule

    (a×10m)(b×10n)=(ab)×10m+n(a\times10^m)(b\times10^n)=(ab)\times10^{m+n}

    Division rule

    a×10mb×10n=ab×10m−n,b≠0\frac{a\times10^m}{b\times10^n}=\frac{a}{b}\times10^{m-n},\quad b\ne0

    Addition with common exponent

    a×10k+b×10k=(a+b)×10ka\times10^k+b\times10^k=(a+b)\times10^k

    Power rule

    (a×10k)n=an×10kn(a\times10^k)^n=a^n\times10^{kn}

    Calculator translation

    aEk=a×10ka\text{E}k=a\times10^k

    Common metric prefixes

    kilo=103,milli=10−3,micro=10−6,nano=10−9\text{kilo}=10^3,\quad \text{milli}=10^{-3},\quad \text{micro}=10^{-6},\quad \text{nano}=10^{-9}

    Normalized form

    N=a×10k,1≤∣a∣<10,k∈ZN=a\times10^k,\quad 1\le |a|<10,\quad k\in\mathbb Z

    Product

    (a×10m)(b×10n)=ab×10m+n(a\times10^m)(b\times10^n)=ab\times10^{m+n}

    Quotient

    a×10mb×10n=ab×10m−n\frac{a\times10^m}{b\times10^n}=\frac ab\times10^{m-n}

    Power

    (a×10m)r=ar×10mr(a\times10^m)^r=a^r\times10^{mr}

    Common-exponent sum

    a×10k+b×10k=(a+b)×10ka\times10^k+b\times10^k=(a+b)\times10^k
    Topic 1.2Not started

    Arithmetic sequences and series

    Arithmetic sequences model quantities with constant or approximately constant additive change. This AI SL lesson connects terms, finite sums, sigma notation, technology and real-data interpretation from first principles.

    190 min estimated

    Topic 1.2 progress0%
    Learning objectives
    • Distinguish a sequence of ordered terms from the series formed by adding those terms.
    • Recognize an arithmetic sequence and identify its first term and common difference.
    • Generate terms using the recurrence relation un+1=un+du_{n+1}=u_n+d.
    • Use un=a+(n−1)du_n=a+(n-1)d to find any term directly.
    • Find an unknown first term, common difference, term value or term number from given information.
    • Calculate finite arithmetic-series sums using either the first and last terms or the first term and common difference.
    • Find the number of terms from a term or sum condition and check integer constraints.
    • Interpret and evaluate sigma notation for finite arithmetic sums.
    • Build arithmetic models for simple interest, seating, saving, production and other constant-change contexts.
    • Use tables, spreadsheets, graphing tools and equation solvers while still identifying the first term and common difference.
    • Approximate the common difference when real data are not perfectly arithmetic and evaluate the model limitations.
    • Communicate an IB AI SL solution with formulas, units, technology evidence, validation and contextual conclusions.
    Key formulas

    First n terms as a series

    Sn=u1+u2+⋯+unS_n=u_1+u_2+\cdots+u_n

    Common difference

    d=un+1−und=u_{n+1}-u_n

    Arithmetic recurrence

    u1=a,un+1=un+du_1=a,\qquad u_{n+1}=u_n+d

    Arithmetic nth term

    un=a+(n−1)du_n=a+(n-1)d

    Linear form

    un=dn+(a−d)u_n=dn+(a-d)

    Difference from two terms

    d=uq−upq−p,q≠pd=\frac{u_q-u_p}{q-p},\quad q\ne p

    Sum using first and last terms

    Sn=n2(a+un)S_n=\frac{n}{2}(a+u_n)

    Sum using first term and difference

    Sn=n2[2a+(n−1)d]S_n=\frac{n}{2}[2a+(n-1)d]

    Number times average term

    Sn=n(a+un2)S_n=n\left(\frac{a+u_n}{2}\right)

    Arithmetic sum in sigma notation

    ∑r=1n[a+(r−1)d]=Sn\sum\limits_{r=1}^{n}[a+(r-1)d]=S_n

    Number of indexed terms

    count=q−p+1\text{count}=q-p+1

    Simple-interest amount

    An=P(1+nr)A_n=P(1+nr)

    Simple interest earned

    I=PrnI=Prn

    Approximate difference from two positions

    dapprox=uq−upq−pd_{\text{approx}}=\frac{u_q-u_p}{q-p}

    Residual

    en=observedn−predictedne_n=\text{observed}_n-\text{predicted}_n

    Nth term

    un=a+(n−1)du_n=a+(n-1)d

    Sum from first and last terms

    Sn=n2(a+un)S_n=\frac n2(a+u_n)

    Sum from first term and difference

    Sn=n2[2a+(n−1)d]S_n=\frac n2[2a+(n-1)d]

    Sigma form

    ∑r=1n[a+(r−1)d]=Sn\sum\limits_{r=1}^{n}[a+(r-1)d]=S_n
    Topic 1.3Not started

    Geometric sequences and series

    Geometric sequences model repeated multiplication. This application-focused AI SL lesson develops common ratios, nth terms, finite and relevant infinite sums, technology methods, growth, decay and model evaluation.

    200 min estimated

    Topic 1.3 progress0%
    Learning objectives
    • Distinguish multiplicative geometric change from additive arithmetic change.
    • Identify the first term and common ratio, including fractional and negative ratios.
    • Generate terms from the recurrence relation un+1=runu_{n+1}=ru_n.
    • Use un=arn−1u_n=ar^{n-1} to find a specified term.
    • Find an unknown term, first term, ratio or term number and check all valid solutions.
    • Calculate finite geometric-series sums and handle the special case where the ratio is 1.
    • Decide whether an infinite geometric series converges and find its sum when relevant.
    • Interpret sigma notation for finite and infinite geometric sums.
    • Build and interpret repeated-percentage growth and decay models.
    • Use GDC tables, graphs, solvers, spreadsheets and exponential regression appropriately.
    • Evaluate approximate geometric models using ratios, residuals, interpolation and extrapolation.
    • Present an IB AI SL solution with formulas, units, rounding, integer constraints and contextual conclusions.
    Key formulas

    Consecutive-term ratio

    r=un+1unr=\frac{u_{n+1}}{u_n}

    Growth multiplier

    r=1+p100r=1+\frac{p}{100}

    Decay multiplier

    r=1−p100r=1-\frac{p}{100}

    Geometric recurrence

    u1=a,un+1=runu_1=a,\qquad u_{n+1}=ru_n

    Geometric nth term

    un=arn−1u_n=ar^{n-1}

    Term number from logarithms

    n=1+ln⁡(una)ln⁡rn=1+\frac{\ln(\frac{u_n}{a})}{\ln r}

    Ratio from two terms

    rq−p=uqupr^{q-p}=\frac{u_q}{u_p}

    First term from a known term

    a=uprp−1a=\frac{u_p}{r^{p-1}}

    First n geometric terms

    Sn=a+ar+ar2+⋯+arn−1S_n=a+ar+ar^2+\cdots+ar^{n-1}

    Finite geometric sum

    Sn=a(1−rn)1−r=a(rn−1)r−1S_n=\frac{a(1-r^n)}{1-r}=\frac{a(r^n-1)}{r-1}

    Constant-ratio special case

    Sn=nawhen r=1S_n=na\quad\text{when }r=1

    Finite geometric sum in sigma notation

    ∑k=0n−1ark=a(1−rn)1−r\sum\limits_{k=0}^{n-1}ar^k=\frac{a(1-r^n)}{1-r}

    Inclusive index count

    number of terms=n−m+1\text{number of terms}=n-m+1

    Infinite geometric sum

    S∞=a1−r,∣r∣<1S_\infty=\frac{a}{1-r},\qquad |r|<1

    Infinite sigma form

    ∑k=0∞ark=a1−r,∣r∣<1\sum\limits_{k=0}^{\infty}ar^k=\frac{a}{1-r},\qquad |r|<1

    Repeated-change model

    At=A0rtA_t=A_0r^t

    Percentage change from ratio

    percentage change=100(r−1)%\text{percentage change}=100(r-1)\%

    Approximate ratio from endpoints

    r≈(uqup)1q−pr\approx\left(\frac{u_q}{u_p}\right)^{\frac{1}{q-p}}

    Residual

    en=observed value−predicted valuee_n=\text{observed value}-\text{predicted value}

    Common ratio

    r=un+1unr=\frac{u_{n+1}}{u_n}

    Nth term

    un=arn−1u_n=ar^{n-1}

    Finite sum

    Sn=a(1−rn)1−rS_n=\frac{a(1-r^n)}{1-r}

    Infinite sum

    S∞=a1−rS_\infty=\frac{a}{1-r}
    Topic 1.4Not started

    Financial applications

    Model investments, depreciation, inflation, regular savings and loans using compound growth, financial technology and careful interpretation.

    190 min estimated

    Topic 1.4 progress0%
    Learning objectives
    • Distinguish simple interest from compound interest and select the appropriate model.
    • Convert percentage rates to decimal multipliers for growth, appreciation, decay and depreciation.
    • Calculate future value, present value, interest rate or time using compound-interest models.
    • Match nominal annual rates, periodic rates, compounding frequency and elapsed time consistently.
    • Calculate and interpret effective annual interest rates.
    • Model regular savings deposits using finite geometric-series formulas.
    • Model amortizing loans, calculate periodic repayments and interpret outstanding balances.
    • Use GDC financial or TVM functions with a consistent cash-flow sign convention.
    • Solve financial word problems with appropriate units, accuracy, integer constraints and contextual interpretation.
    • Evaluate whether a financial model and its assumptions are reasonable in a real situation.
    • Calculate the real value of a future amount after allowing for inflation.
    • Compare financial options and evaluate the assumptions, reliability and limitations of a model.
    Key formulas

    Simple interest earned

    I=PrtI=Prt

    Simple-interest balance

    A=P(1+rt)A=P(1+rt)

    Percentage multiplier

    growth: 1+p100,decay: 1−p100\text{growth: }1+\frac{p}{100},\qquad \text{decay: }1-\frac{p}{100}

    Compound future value

    FV=PV(1+i)nFV=PV(1+i)^n

    Periodic rate from two values

    i=(FVPV)1n−1,n>0, PV≠0, FVPV>0i=\left(\frac{FV}{PV}\right)^{\frac{1}{n}}-1,\quad n>0,\ PV\ne0,\frac{\ FV}{PV}>0

    Number of periods

    n=ln⁡(FV/PV)ln⁡(1+i)PV≠0,FV/PV>0,i>−1, i≠0\begin{gathered}n=\frac{\ln(FV/PV)}{\ln(1+i)}\\ PV\ne0,\quad FV/PV>0,\quad i>-1,\ i\ne0\end{gathered}

    Nominal-rate compound interest

    FV=PV(1+rm)mtFV=PV\left(1+\frac{r}{m}\right)^{mt}

    Periodic rate and period count

    i=rm,n=mti=\frac{r}{m},\qquad n=mt

    Effective annual rate

    EAR=(1+rm)m−1EAR=\left(1+\frac{r}{m}\right)^m-1

    Present value of one future amount

    PV=FV(1+i)n=FV(1+i)−nPV=\frac{FV}{(1+i)^n}=FV(1+i)^{-n}

    Appreciation

    Vn=V0(1+a)nV_n=V_0(1+a)^n

    Reducing-balance depreciation

    Vn=V0(1−d)nV_n=V_0(1-d)^n

    Future value of an ordinary annuity

    FV={R(1+i)n−1i,i≠0nR,i=0FV=\begin{cases}R\frac{(1+i)^n-1}{i},&i\ne0\\ nR,&i=0\end{cases}

    Future value of an annuity due

    FVdue={R(1+i)n−1i(1+i),i≠0nR,i=0FV_{\mathrm{due}}=\begin{cases}R\frac{(1+i)^n-1}{i}(1+i),&i\ne0\\ nR,&i=0\end{cases}

    Deposit required for a target

    R={FVi(1+i)n−1,i≠0FV/n,i=0R=\begin{cases}FV\frac{i}{(1+i)^n-1},&i\ne0\\ FV/n,&i=0\end{cases}

    Present value of loan repayments

    PV={R1−(1+i)−ni,i≠0nR,i=0PV=\begin{cases}R\frac{1-(1+i)^{-n}}{i},&i\ne0\\ nR,&i=0\end{cases}

    Periodic loan repayment

    R={PVi1−(1+i)−n,i≠0PV/n,i=0R=\begin{cases}PV\frac{i}{1-(1+i)^{-n}},&i\ne0\\ PV/n,&i=0\end{cases}

    Outstanding balance after k payments

    Bk={PV(1+i)k−R(1+i)k−1i,i≠0PV−kR,i=0B_k=\begin{cases}PV(1+i)^k-R\frac{(1+i)^k-1}{i},&i\ne0\\ PV-kR,&i=0\end{cases}

    Total interest on equal repayments

    Itotal=Rn−PVI_{\mathrm{total}}=Rn-PV

    Future price under inflation

    Ct=C0(1+f)tC_t=C_0(1+f)^t

    Real value after inflation

    Vreal=M(1+f)tV_{\mathrm{real}}=\frac{M}{(1+f)^t}

    Exact real annual rate

    rreal=1+r1+f−1r_{\mathrm{real}}=\frac{1+r}{1+f}-1

    Simple interest

    I=Prt,A=P(1+rt)I=Prt,\qquad A=P(1+rt)

    Compound amount

    FV=PV(1+i)NFV=PV(1+i)^N

    Nominal compounding

    i=rm,N=mti=\frac{r}{m},\qquad N=mt

    Present value

    PV=FV(1+i)NPV=\frac{FV}{(1+i)^N}

    Depreciation

    VN=V0(1−d)NV_N=V_0(1-d)^N

    Regular savings

    FV=PMT((1+i)N−1i)FV=PMT\left(\frac{(1+i)^N-1}{i}\right)

    Loan payment

    PMT=PV(i1−(1+i)−N)PMT=PV\left(\frac{i}{1-(1+i)^{-N}}\right)
    Topic 1.5Not started

    Integer exponents and logarithms

    Integer exponents model repeated growth and reciprocal change, while logarithms reverse exponentiation. This application-focused guide develops exponent laws, logarithmic notation, equation solving, growth and decay models, logarithmic scales, GDC methods, and IB AI SL interpretation.

    170 min estimated

    Topic 1.5 progress0%
    Learning objectives
    • Interpret positive, zero and negative integer exponents, including all restrictions needed for an expression to be defined.
    • Apply the product, quotient, power, product-to-a-power and quotient-to-a-power laws accurately.
    • Simplify numerical and algebraic expressions involving powers and rewrite answers with positive exponents when required.
    • Explain a logarithm as an exponent and convert fluently between exponential and logarithmic form.
    • Use basic logarithm laws with valid positive arguments and recognize expressions that cannot be split.
    • Solve exponential equations exactly when a common base is available and numerically using logarithms or a GDC otherwise.
    • Solve simple logarithmic equations and reject solutions that violate domain restrictions.
    • Build, use and interpret exponential growth and decay models in real-world contexts.
    • Use logarithmic scales such as pH, decibels and earthquake magnitude to compare real quantities.
    • Use calculator and GDC power, logarithm, graph, table and solver methods efficiently.
    • Communicate IB AI SL solutions with equations, units, suitable accuracy, integer constraints and model limitations.
    Key formulas

    Positive integer exponent

    an=a⋅a⋯a⏟n factors,n∈Na^n=\underbrace{a\cdot a\cdots a}_{n\text{ factors}},\quad n\in\mathbb N

    Zero exponent

    a0=1,a≠0a^0=1,\quad a\ne0

    Negative integer exponent

    a−n=1an,a≠0a^{-n}=\frac{1}{a^n},\quad a\ne0

    Product law

    aman=am+na^m a^n=a^{m+n}

    Quotient law

    aman=am−n,a≠0\frac{a^m}{a^n}=a^{m-n},\quad a\ne0

    Power of a power

    (am)n=amn(a^m)^n=a^{mn}

    Power of a product

    (ab)n=anbn(ab)^n=a^n b^n

    Power of a quotient

    (ab)n=anbn,b≠0\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n},\quad b\ne0

    Moving a negative power across a fraction bar

    a−mb−n=bnam,a,b≠0\frac{a^{-m}}{b^{-n}}=\frac{b^n}{a^m},\quad a,b\ne0

    Exponential-logarithmic equivalence

    ac=b⟺log⁡ab=ca^c=b\quad\Longleftrightarrow\quad\log_a b=c

    Common and natural logarithms

    log⁡x=log⁡10x,ln⁡x=log⁡ex\log x=\log_{10}x,\qquad\ln x=\log_e x

    Inverse identities

    log⁡a(ax)=x,alog⁡ax=x(x>0)\log_a(a^x)=x,\qquad a^{\log_a x}=x\quad(x>0)

    Product property

    log⁡a(xy)=log⁡ax+log⁡ay\log_a(xy)=\log_a x+\log_a y

    Quotient property

    log⁡a(xy)=log⁡ax−log⁡ay\log_a\left(\frac{x}{y}\right)=\log_a x-\log_a y

    Power property

    log⁡a(xk)=klog⁡ax\log_a(x^k)=k\log_a x

    Useful exact values

    log⁡a1=0,log⁡aa=1\log_a1=0,\qquad\log_a a=1

    Common-base principle

    af(x)=ag(x)⟹f(x)=g(x),a>0, a≠1a^{f(x)}=a^{g(x)}\Longrightarrow f(x)=g(x),\quad a>0,\ a\ne1

    Solving a basic exponential equation

    ax=b⟹x=ln⁡bln⁡a,a>0, a≠1, b>0a^x=b\Longrightarrow x=\frac{\ln b}{\ln a},\quad a>0,\ a\ne1,\ b>0

    Single logarithm equation

    log⁡af(x)=c⟺f(x)=ac,f(x)>0\log_a f(x)=c\Longleftrightarrow f(x)=a^c,\quad f(x)>0

    Equality of logarithms

    log⁡af(x)=log⁡ag(x)⟹f(x)=g(x),f(x),g(x)>0\log_a f(x)=\log_a g(x)\Longrightarrow f(x)=g(x),\quad f(x),g(x)>0

    Exponential growth or decay model

    Q(t)=Q0btQ(t)=Q_0b^t

    Percentage multiplier

    b=1±r100b=1\pm\frac{r}{100}

    Time to a target

    t=ln⁡(TQ0)ln⁡bt=\frac{\ln(\frac{T}{Q_0})}{\ln b}

    pH model

    pH=−log⁡10[H+]\mathrm{pH}=-\log_{10}[\mathrm H^+]

    Sound-intensity level

    L=10log⁡10(II0)L=10\log_{10}\left(\frac{I}{I_0}\right)

    Ratio from a base-10 scale difference

    ratio=10Δ\text{ratio}=10^{\Delta}

    Change-of-base formula

    log⁡ab=log⁡blog⁡a=ln⁡bln⁡a\log_a b=\frac{\log b}{\log a}=\frac{\ln b}{\ln a}

    Product and quotient laws

    aman=am+n,aman=am−na^ma^n=a^{m+n},\qquad\frac{a^m}{a^n}=a^{m-n}

    Power laws

    (am)n=amn,(ab)n=anbn(a^m)^n=a^{mn},\qquad(ab)^n=a^nb^n

    Zero and negative exponents

    a0=1,a−n=1an(a≠0)a^0=1,\qquad a^{-n}=\frac1{a^n}\quad(a\ne0)

    Exponential-logarithmic equivalence

    ax=b⟺log⁡ab=xa^x=b\Longleftrightarrow\log_a b=x

    Change of base

    log⁡ab=log⁡blog⁡a=ln⁡bln⁡a\log_a b=\frac{\log b}{\log a}=\frac{\ln b}{\ln a}

    Growth or decay model

    Q(t)=Q0btQ(t)=Q_0b^t
    Topic 1.6Not started

    Approximation, bounds and percentage error

    Reported values are often rounded measurements rather than exact numbers. This application-focused guide develops appropriate accuracy, decimal places, significant figures, error intervals, worst-case bounds, absolute and percentage error, accumulated rounding effects, GDC methods, and reliable interpretation in context.

    180 min estimated

    Topic 1.6 progress0%
    Learning objectives
    • Distinguish exact values from measurements and approximations and select an appropriate degree of accuracy for a context.
    • Round positive and negative values correctly to a stated number of decimal places or significant figures.
    • Identify the rounding unit and construct lower and upper bounds using half of that unit.
    • Write and interpret error intervals using the correct inclusive lower and exclusive upper endpoint.
    • Use bounds to find possible ranges for sums, differences, products, quotients, areas, volumes and rates.
    • Calculate and interpret absolute error, relative error and percentage error when a reference value is known.
    • Determine maximum possible errors caused by rounded measurements when an exact value is unknown.
    • Explain how premature rounding and repeated calculations can affect a final result and retain suitable guard digits.
    • Apply approximation and error methods to measurement, finance, science, construction and data contexts.
    • Use calculator and GDC tools to estimate, verify, graph and report answers with appropriate accuracy.
    • Communicate IB AI SL solutions with inequalities, units, reasoning, assumptions and a reasonableness check.
    Key formulas

    Rounding unit for decimal places

    u=10−du=10^{-d}

    General rounding error interval

    r−u2≤x<r+u2r-\frac{u}{2}\le x<r+\frac{u}{2}

    Lower and upper bounds

    xL=r−u2,xU=r+u2x_{\mathrm L}=r-\frac{u}{2},\qquad x_{\mathrm U}=r+\frac{u}{2}

    Interval notation

    x∈[xL,xU)x\in[x_{\mathrm L},x_{\mathrm U})

    Sum bounds

    SL=aL+bL,SU=aU+bUS_{\mathrm L}=a_{\mathrm L}+b_{\mathrm L},\qquad S_{\mathrm U}=a_{\mathrm U}+b_{\mathrm U}

    Difference bounds

    DL=aL−bU,DU=aU−bLD_{\mathrm L}=a_{\mathrm L}-b_{\mathrm U},\qquad D_{\mathrm U}=a_{\mathrm U}-b_{\mathrm L}

    Product bounds for positive values

    PL=aLbL,PU=aUbUP_{\mathrm L}=a_{\mathrm L}b_{\mathrm L},\qquad P_{\mathrm U}=a_{\mathrm U}b_{\mathrm U}

    Quotient bounds for positive values

    QL=aLbU,QU=aUbLQ_{\mathrm L}=\frac{a_{\mathrm L}}{b_{\mathrm U}},\qquad Q_{\mathrm U}=\frac{a_{\mathrm U}}{b_{\mathrm L}}

    Absolute error

    Ea=∣xapprox−xexact∣E_{\mathrm a}=\left|x_{\mathrm{approx}}-x_{\mathrm{exact}}\right|

    Relative error

    Er=Ea∣xexact∣,xexact≠0E_{\mathrm r}=\frac{E_{\mathrm a}}{|x_{\mathrm{exact}}|},\qquad x_{\mathrm{exact}}\ne0

    Percentage error

    E%=∣xapprox−xexact∣∣xexact∣×100%E_{\%}=\frac{|x_{\mathrm{approx}}-x_{\mathrm{exact}}|}{|x_{\mathrm{exact}}|}\times100\%

    Maximum absolute rounding error

    Emax⁡=u2E_{\max}=\frac{u}{2}

    Maximum output percentage error

    E%,max⁡=max⁡(∣yU−y0∣,∣y0−yL∣)∣y0∣×100%E_{\%,\max}=\frac{\max\left(|y_{\mathrm U}-y_0|,|y_0-y_{\mathrm L}|\right)}{|y_0|}\times100\%

    Symmetric tolerance

    t−δ≤x≤t+δt-\delta\le x\le t+\delta

    Decimal-place unit

    u=10−du=10^{-d}

    Error interval

    r−u2≤x<r+u2r-\frac{u}{2}\le x<r+\frac{u}{2}

    Maximum rounding error

    Emax⁡=u2E_{\max}=\frac{u}{2}

    Absolute error

    Ea=∣xapprox−xexact∣E_{\mathrm a}=|x_{\mathrm{approx}}-x_{\mathrm{exact}}|

    Relative error

    Er=Ea∣xexact∣E_{\mathrm r}=\frac{E_{\mathrm a}}{|x_{\mathrm{exact}}|}

    Percentage error

    E%=100Er%E_{\%}=100E_{\mathrm r}\%

    Positive product bounds

    PL=aLbL,PU=aUbUP_{\mathrm L}=a_{\mathrm L}b_{\mathrm L},\qquad P_{\mathrm U}=a_{\mathrm U}b_{\mathrm U}

    Positive quotient bounds

    QL=aLbU,QU=aUbLQ_{\mathrm L}=\frac{a_{\mathrm L}}{b_{\mathrm U}},\qquad Q_{\mathrm U}=\frac{a_{\mathrm U}}{b_{\mathrm L}}
    Topic 1.7Not started

    Amortization and annuities

    Annuities model equal payments made at regular intervals, while amortization explains how loan payments divide between interest and principal. This technology-led guide develops cash-flow timing, present and future value, loan repayments, outstanding balances, amortization schedules, savings plans, spreadsheets, TVM/GDC methods, and IB AI SL interpretation.

    185 min estimated

    Topic 1.7 progress0%
    Learning objectives
    • Explain an annuity as a finite sequence of equal cash flows made at regular intervals.
    • Distinguish ordinary annuities from annuities due and identify the timing of the first and last payment.
    • Convert annual rates and time spans into a consistent periodic rate and total number of payment periods.
    • Use financial technology to find the future value of regular deposits and the deposit required for a target.
    • Use present value to model regular withdrawals, pensions, leases and loan repayments.
    • Explain amortization and calculate a regular loan payment using a GDC or spreadsheet.
    • Separate each loan payment into interest and principal components and construct an amortization schedule.
    • Determine and interpret an outstanding balance after a specified number of payments.
    • Calculate total payments and total interest and compare realistic financial options.
    • Use TVM variables, payment frequencies, END/BEGIN settings and cash-flow signs consistently.
    • Validate financial-technology output using estimation, formula structure, units and contextual constraints.
    • Communicate IB AI SL financial solutions with assumptions, suitable currency rounding and interpretation.
    Key formulas

    Annuity-due timing adjustment

    Vdue=Vordinary(1+i)V_{\mathrm{due}}=V_{\mathrm{ordinary}}(1+i)

    Periodic rate

    i=rmi=\frac{r}{m}

    Number of periods

    n=mtn=mt

    Effective annual rate

    reff=(1+i)m−1r_{\mathrm{eff}}=(1+i)^m-1

    Future value of an ordinary annuity

    FV=R(1+i)n−1iFV=R\frac{(1+i)^n-1}{i}

    Future value of an annuity due

    FVdue={R(1+i)n−1i(1+i),i≠0nR,i=0FV_{\mathrm{due}}=\begin{cases}R\frac{(1+i)^n-1}{i}(1+i),&i\ne0\\ nR,&i=0\end{cases}

    Regular deposit for a target

    R=FVi(1+i)n−1R=FV\frac{i}{(1+i)^n-1}

    Interest earned on a savings annuity

    I=FV−nRI=FV-nR

    Present value of an ordinary annuity

    PV=R1−(1+i)−niPV=R\frac{1-(1+i)^{-n}}{i}

    Present value of an annuity due

    PVdue=R1−(1+i)−ni(1+i)PV_{\mathrm{due}}=R\frac{1-(1+i)^{-n}}{i}(1+i)

    Loan as a present-value annuity

    PV=R1−(1+i)−niPV=R\frac{1-(1+i)^{-n}}{i}

    Periodic loan repayment

    R={PVi1−(1+i)−n,i≠0PV/n,i=0R=\begin{cases}PV\frac{i}{1-(1+i)^{-n}},&i\ne0\\ PV/n,&i=0\end{cases}

    Total scheduled repayments

    T=nRT=nR

    Total interest without fees

    Itotal=nR−PVI_{\mathrm{total}}=nR-PV

    Outstanding balance from original loan

    Bk=PV(1+i)k−R(1+i)k−1iB_k=PV(1+i)^k-R\frac{(1+i)^k-1}{i}

    Outstanding balance from remaining payments

    Bk=R1−(1+i)−(n−k)iB_k=R\frac{1-(1+i)^{-(n-k)}}{i}

    Principal repaid by time k

    Prepaid=PV−BkP_{\mathrm{repaid}}=PV-B_k

    Interest component

    Ij=iBj−1I_j=iB_{j-1}

    Principal component

    Pj=R−IjP_j=R-I_j

    Balance recurrence

    Bj=Bj−1(1+i)−RB_j=B_{j-1}(1+i)-R

    Periodic rate and period count

    i=rm,n=mti=\frac{r}{m},\qquad n=mt

    Ordinary-annuity future value

    FV=R(1+i)n−1iFV=R\frac{(1+i)^n-1}{i}

    Annuity-due adjustment

    Vdue=Vordinary(1+i)V_{\mathrm{due}}=V_{\mathrm{ordinary}}(1+i)

    Ordinary-annuity present value

    PV=R1−(1+i)−niPV=R\frac{1-(1+i)^{-n}}{i}

    Loan repayment

    R=PVi1−(1+i)−nR=PV\frac{i}{1-(1+i)^{-n}}

    Outstanding balance

    Bk=PV(1+i)k−R(1+i)k−1iB_k=PV(1+i)^k-R\frac{(1+i)^k-1}{i}

    Amortization row

    Ij=iBj−1,Pj=R−Ij,Bj=Bj−1−PjI_j=iB_{j-1},\qquad P_j=R-I_j,\qquad B_j=B_{j-1}-P_j

    Total interest

    Itotal=nR−PVI_{\mathrm{total}}=nR-PV
    Topic 1.8Not started

    Solving equations with technology

    Technology can locate numerical solutions, zeros, roots and intersections efficiently, but students must still build the correct equation, choose a meaningful domain and window, find every required solution, and validate the output. This guide develops the AI SL requirements for systems of up to three linear equations and polynomial equations, then extends the same GDC workflow to graphical, tabular, exponential, logarithmic and contextual problems.

    205 min estimated

    Topic 1.8 progress0%
    Learning objectives
    • Explain a solution as a value that makes an equation true and distinguish a verified solution from a calculator candidate.
    • Represent the equation f(x)=g(x)f(x)=g(x) either as an intersection problem or as the zero problem f(x)−g(x)=0f(x)-g(x)=0.
    • Use graphs, numerical solvers and tables to locate approximate solutions.
    • Use technology to solve systems of two or three linear equations and interpret the ordered solution.
    • Enter polynomial coefficients correctly, including zero coefficients for missing powers, and find all real roots.
    • Solve selected nonlinear, exponential and logarithmic equations using appropriate technology.
    • Choose domains and graph windows that reveal all solutions relevant to the problem.
    • Distinguish exact solutions from decimal approximations and report suitable accuracy.
    • Interpret GDC messages, roots, intersections and numerical solver outputs rather than copying the display blindly.
    • Check solutions by substitution, residuals, domain restrictions and contextual constraints.
    • Recognize repeated roots, missed roots, extraneous candidates and solutions outside a real-world domain.
    • Present an IB AI SL solution with the mathematical model, technological method, results and contextual conclusion.
    Key formulas

    Root definition

    h(r)=0h(r)=0

    Intersection-to-zero conversion

    f(x)=g(x)  ⟺  f(x)−g(x)=0f(x)=g(x)\iff f(x)-g(x)=0

    Absolute residual

    R=∣LHS−RHS∣R=\left|\text{LHS}-\text{RHS}\right|

    Polynomial factor and root

    (x−r)m is a factor⟹r is a root of multiplicity m(x-r)^m\text{ is a factor}\Longrightarrow r\text{ is a root of multiplicity }m

    Break-even equation

    R(x)=C(x)R(x)=C(x)

    Difference function for intersections

    h(x)=f(x)−g(x)h(x)=f(x)-g(x)

    Sign-change bracket

    h(a)h(b)<0⟹at least one root in (a,b) if h is continuoush(a)h(b)\lt0\Longrightarrow\text{at least one root in }(a,b)\text{ if }h\text{ is continuous}

    Two-variable linear system

    a1x+b1y=c1,a2x+b2y=c2a_1x+b_1y=c_1,\qquad a_2x+b_2y=c_2

    Three-variable linear system

    aix+biy+ciz=di(i=1,2,3)a_ix+b_iy+c_iz=d_i\qquad(i=1,2,3)

    Polynomial standard form

    anxn+an−1xn−1+⋯+a1x+a0=0,an≠0a_nx^n+a_{n-1}x^{n-1}+\cdots+a_1x+a_0=0,\qquad a_n\ne0

    Maximum number of distinct real roots

    number of distinct real roots≤n\text{number of distinct real roots}\le n

    Even-root restriction

    u(x) requires u(x)≥0\sqrt{u(x)}\text{ requires }u(x)\ge0

    Logarithm restriction

    log⁡b(u(x)) requires u(x)>0\log_b(u(x))\text{ requires }u(x)\gt0

    Denominator restriction

    p(x)q(x) requires q(x)≠0\frac{p(x)}{q(x)}\text{ requires }q(x)\ne0

    Exponential solution check

    abx=c⟹x=ln⁡(ca)ln⁡bab^x=c\Longrightarrow x=\frac{\ln(\frac{c}{a})}{\ln b}

    Logarithm argument condition

    log⁡bu is real only when u>0\log_b u\text{ is real only when }u\gt0

    Approximate equality symbol

    x≈1.732x\approx1.732

    Exact equality symbol

    x=3x=\sqrt3

    Zero residual

    R=∣h(r)∣R=|h(r)|

    Intersection residual

    R=∣f(r)−g(r)∣R=|f(r)-g(r)|

    Zero and intersection equivalence

    f(x)=g(x)  ⟺  f(x)−g(x)=0f(x)=g(x)\iff f(x)-g(x)=0

    Sign-change bracket

    h(a)h(b)<0h(a)h(b)\lt0

    Residual

    R=∣LHS−RHS∣R=|\text{LHS}-\text{RHS}|

    Polynomial form

    anxn+⋯+a1x+a0=0a_nx^n+\cdots+a_1x+a_0=0

    Two-variable system

    a1x+b1y=c1,a2x+b2y=c2a_1x+b_1y=c_1,\quad a_2x+b_2y=c_2
  2. Unit 2
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    Functions

    Functions are the central modelling language of AI SL. Students graph, fit and compare linear, quadratic, exponential, power, cubic and sinusoidal models and then use those models to interpret and predict real behaviour. Technology is integrated throughout.

    6 topics

    Unit 2 progress0%
  3. Unit 3
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    Geometry and Trigonometry

    Geometry and Trigonometry in AI SL is strongly practical. Students solve two- and three-dimensional measurement problems, use triangle trigonometry, work with arcs and sectors, construct perpendicular bisectors and interpret Voronoi diagrams for nearest-location problems.

    6 topics

    Unit 3 progress0%
  4. Unit 4
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    Statistics and Probability

    Statistics and Probability is the largest AI SL topic by recommended teaching time. The course emphasizes choosing suitable techniques, using technology correctly and interpreting what statistical output means. Calculation is important, but statistical judgment is equally important.

    11 topics

    Unit 4 progress0%
  5. Unit 5
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    Calculus

    Calculus in AI SL is introductory and application-focused. Students interpret rates of change, identify increasing and decreasing behaviour, find tangents and normals, optimize quantities and use integration for area. Technology supports the process, but basic derivative and antiderivative skills are still required.

    8 topics

    Unit 5 progress0%