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Physics

A concept-based Higher Level syllabus extending motion, matter, waves, fields, and nuclear and quantum physics through rotational mechanics, relativity, thermodynamics, induction, and quantum theory.

Course units

5

Estimated study time

180 hours

Overall completion0%

Course Overview

IB Physics HL is organized into 5 units and 24 focused topics with 299 Key Concepts sections, 0 questions, and 480 flashcards.

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Begin with Topic A.1: Kinematics.

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Your learning path

Course units

Each unit groups focused topics. Every topic follows the same clear rhythm: review Key Concepts, use the Question Bank, then strengthen recall.

  1. Unit 1
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    Space, Time and Motion

    Theme A begins with classical mechanics and then extends the idea of motion into rotation and relativistic spacetime. The HL-only A.4 and A.5 subtopics are major additions and should be learned as conceptual extensions of familiar linear motion, momentum and energy.

    42 hours estimated ·5 topics

    Unit 1 progress0%

    Topics in this unit

    Topic A.1Not started

    Kinematics

    Kinematics describes motion through position, displacement, velocity and acceleration. Students connect equations with vector representations and motion graphs, then apply the same ideas to projectile motion.

    540 min estimated

    Topic A.1 progress0%
    Learning objectives
    • Distinguish scalar distance and speed from vector displacement and velocity.
    • Calculate average and instantaneous velocity, speed and acceleration.
    • Use gradients and areas on position–time, velocity–time and acceleration–time graphs.
    • Apply constant-acceleration equations with a consistent sign convention.
    • Resolve projectile motion into independent horizontal and vertical components.
    • Describe qualitatively how resistance in a fluid changes a trajectory and produces terminal speed.
    Key formulas

    Displacement from position

    Δx=xf−xi\Delta x=x_{\mathrm{f}}-x_{\mathrm{i}}

    Average acceleration

    aˉ=ΔvΔt\bar{a}=\frac{\Delta v}{\Delta t}

    Average speed

    average speed=total distanceΔt\text{average speed}=\frac{\text{total distance}}{\Delta t}

    Average velocity

    vˉ=ΔxΔt\bar{v}=\frac{\Delta x}{\Delta t}

    Instantaneous velocity

    v=dxdtv=\frac{\mathrm{d}x}{\mathrm{d}t}

    Instantaneous acceleration

    a=dvdta=\frac{\mathrm{d}v}{\mathrm{d}t}

    Speed from one-dimensional velocity

    speed=∣v∣\text{speed}=|v|

    Velocity from a position–time graph

    v=gradient of the x-t graphv=\text{gradient of the }x\text{-}t\text{ graph}

    Displacement from a velocity–time graph

    Δx=∫t1t2v dt\Delta x=\int_{t_1}^{t_2}v\,\mathrm{d}t

    Distance from a velocity–time graph

    distance=∫t1t2∣v∣ dt\text{distance}=\int_{t_1}^{t_2}|v|\,\mathrm{d}t

    Velocity change from an acceleration–time graph

    Δv=∫t1t2a dt\Delta v=\int_{t_1}^{t_2}a\,\mathrm{d}t

    Displacement from mean velocity

    s=12(u+v)ts=\frac{1}{2}(u+v)t

    Velocity after time

    v=u+atv=u+at

    Displacement after time

    s=ut+12at2s=ut+\frac{1}{2}at^2

    Time-independent equation

    v2=u2+2asv^2=u^2+2as

    Vertical acceleration with upward positive

    ay=−g≈−9.81 m s−2a_y=-g\approx-9.81\,\mathrm{m\,s^{-2}}

    Initial velocity components

    ux=ucos⁡θ,uy=usin⁡θu_x=u\cos\theta,\qquad u_y=u\sin\theta

    Ideal horizontal motion

    x=x0+uxt,vx=uxx=x_0+u_xt,\qquad v_x=u_x

    Ideal vertical motion

    y=y0+uyt−12gt2,vy=uy−gty=y_0+u_yt-\frac{1}{2}gt^2,\qquad v_y=u_y-gt

    Speed from perpendicular components

    v=vx2+vy2v=\sqrt{v_x^2+v_y^2}

    Flight time, range and maximum rise: check the conditions

    T=2usin⁡θg,R=u2sin⁡(2θ)g,H=u2sin⁡2θ2gT=\frac{2u\sin\theta}{g},\quad R=\frac{u^2\sin(2\theta)}{g},\quad H=\frac{u^2\sin^2\theta}{2g}

    Terminal-speed condition

    Fresultant=0⇒a=0F_{\mathrm{resultant}}=0\quad\Rightarrow\quad a=0

    Simplified vertical balance

    Fdrag=mgat terminal speed (if buoyancy is negligible)F_{\mathrm{drag}}=mg\quad\text{at terminal speed (if buoyancy is negligible)}
    Topic A.2Not started

    Forces and momentum

    This subtopic uses Newton’s laws and momentum to explain changes in motion. It also introduces circular motion as a continuous change of velocity direction caused by a resultant inward force.

    600 min estimated

    Topic A.2 progress0%
    Learning objectives
    • Apply Newton’s three laws and identify valid action–reaction pairs.
    • Draw free-body diagrams and resolve forces into useful components.
    • Model normal force, tension, friction, spring force, viscous drag and buoyancy.
    • Use momentum and impulse in collisions, explosions and force–time situations.
    • Apply conservation of momentum to isolated systems.
    • Analyse uniform circular motion using centripetal acceleration and resultant force.
    Key formulas

    Resultant external force

    F⃗net=F⃗1+F⃗2+⋯+F⃗n\vec F_{\mathrm{net}}=\vec F_1+\vec F_2+\cdots+\vec F_n

    Newton's second law in momentum form

    F⃗net=dp⃗dt\vec F_{\mathrm{net}}=\frac{\mathrm{d}\vec p}{\mathrm{d}t}

    Newton's second law for constant mass

    F⃗net=ma⃗\vec F_{\mathrm{net}}=m\vec a

    Translational equilibrium

    F⃗net=0⇒a⃗=0\vec F_{\mathrm{net}}=0\quad\Rightarrow\quad \vec a=0

    Weight near Earth's surface

    W=mgW=mg

    Newton's second law by components

    Fnet,x=max,Fnet,y=mayF_{\mathrm{net},x}=ma_x,\qquad F_{\mathrm{net},y}=ma_y

    Newton's third law

    F⃗A→B=−F⃗B→A\vec F_{A\to B}=-\vec F_{B\to A}

    Weight components on an incline

    W∥=mgsin⁡θ,W⊥=mgcos⁡θW_{\parallel}=mg\sin\theta,\qquad W_{\perp}=mg\cos\theta

    Normal force on a simple incline

    N=mgcos⁡θif a⊥=0 and no other perpendicular force actsN=mg\cos\theta\quad\text{if }a_\perp=0\text{ and no other perpendicular force acts}

    Static-friction range

    0≤fs≤μsN0\le f_s\le \mu_sN

    Limiting and kinetic friction

    fs,max⁡=μsN,fk=μkNf_{s,\max}=\mu_sN,\qquad f_k=\mu_kN

    Ideal-string tension

    T1=T2=TT_1=T_2=T

    Hooke's law

    F⃗s=−kx⃗andFs=k∣x⃗∣ in magnitude\vec F_s=-k\vec x\qquad\text{and}\qquad F_s=k|\vec x|\ \text{in magnitude}

    Archimedes' principle

    Fb=ρfluidVdisplacedgF_b=\rho_{\mathrm{fluid}}V_{\mathrm{displaced}}g

    Stokes' law

    Fd=6πηrvF_d=6\pi\eta rv

    Terminal-motion balance

    W=Fb+Fdfor steady downward motion in still fluid with no other forcesW=F_b+F_d\quad\text{for steady downward motion in still fluid with no other forces}

    Momentum

    p⃗=mv⃗\vec p=m\vec v

    Net external impulse

    J⃗net=Δp⃗=∫t1t2F⃗net dt\vec J_{\mathrm{net}}=\Delta\vec p=\int_{t_1}^{t_2}\vec F_{\mathrm{net}}\,\mathrm{d}t

    Average resultant external force

    F⃗net,avg=Δp⃗Δt\vec F_{\mathrm{net,avg}}=\frac{\Delta\vec p}{\Delta t}

    Momentum conservation

    P⃗before=P⃗afterwhen external impulse is negligible\vec P_{\mathrm{before}}=\vec P_{\mathrm{after}}\quad\text{when external impulse is negligible}

    Translational kinetic energy

    K=12mv2K=\frac{1}{2}mv^2

    Speed, period and angular speed (uniform circular motion)

    v=2πrT=ωrv=\frac{2\pi r}{T}=\omega r

    Angular speed and period (uniform circular motion)

    ω=2πT\omega=\frac{2\pi}{T}

    Centripetal acceleration

    ac=v2r=ω2r,ac=4π2rT2 for uniform motiona_c=\frac{v^2}{r}=\omega^2r,\qquad a_c=\frac{4\pi^2r}{T^2}\ \text{for uniform motion}

    Required radial resultant

    Fradial=mac=mv2rF_{\mathrm{radial}}=ma_c=\frac{mv^2}{r}
    Topic A.3Not started

    Work, energy and power

    Energy methods provide an alternative to force-by-force analysis. Students use work, kinetic and gravitational potential energy, efficiency and power to understand how systems transfer and transform energy.

    480 min estimated

    Topic A.3 progress0%
    Learning objectives
    • Calculate work done by a constant force, including forces at an angle to displacement.
    • Use the work–energy principle and conservation of energy.
    • Calculate kinetic and near-Earth gravitational potential energy.
    • Interpret force–displacement graphs as work transferred.
    • Calculate power from work or energy transfer rate and from force and velocity.
    • Analyse efficiency and Sankey-type energy-transfer representations.
    Key formulas

    Conservation of total energy

    Einitial=EfinalE_{\mathrm{initial}}=E_{\mathrm{final}}

    Average power

    Pavg=ΔEΔt=WΔtP_{\mathrm{avg}}=\frac{\Delta E}{\Delta t}=\frac{W}{\Delta t}

    Efficiency

    η=EusefulEinput=PusefulPinput\eta=\frac{E_{\mathrm{useful}}}{E_{\mathrm{input}}}=\frac{P_{\mathrm{useful}}}{P_{\mathrm{input}}}

    Work by a constant force

    W=Fscos⁡θW=Fs\cos\theta

    Work by the parallel component

    W=F∥sW=F_{\parallel}s

    Work from a variable force

    W=signed area under the F∥ against s graphW=\text{signed area under the }F_{\parallel}\text{ against }s\text{ graph}

    Translational kinetic energy

    Ek=12mv2=p22mE_k=\frac12mv^2=\frac{p^2}{2m}

    Work–energy theorem

    Wnet=ΔEk=12m(v2−u2)W_{\mathrm{net}}=\Delta E_k=\frac12m(v^2-u^2)

    Change in gravitational potential energy

    ΔEg=mgΔh\Delta E_g=mg\Delta h

    Gravitational potential energy from a chosen zero

    Eg=mghE_g=mgh

    Work done by gravity

    Wg=−ΔEgW_g=-\Delta E_g

    Hooke's law

    Fs=−kxF_s=-kx

    Elastic potential energy

    Es=12kx2E_s=\frac12kx^2

    Change in elastic potential energy

    ΔEs=12k(x22−x12)\Delta E_s=\frac12k(x_2^2-x_1^2)

    Mechanical energy

    Emech=Ek+Eg+EsE_{\mathrm{mech}}=E_k+E_g+E_s

    Ideal mechanical-energy conservation

    Ek,i+Eg,i+Es,i=Ek,f+Eg,f+Es,fE_{k,i}+E_{g,i}+E_{s,i}=E_{k,f}+E_{g,f}+E_{s,f}

    System energy change when work is the only boundary energy transfer

    Wext=ΔEsystemW_{\mathrm{ext}}=\Delta E_{\mathrm{system}}

    Thermal transfer by constant kinetic friction

    ΔEth=fks\Delta E_{\mathrm{th}}=f_k s

    Non-conservative work

    Wnc=ΔEmechW_{\mathrm{nc}}=\Delta E_{\mathrm{mech}}

    Idealized braking distance

    d=mv22Fbd=\frac{mv^2}{2F_b}

    Average power

    Pavg=WΔt=ΔEΔtP_{\mathrm{avg}}=\frac{W}{\Delta t}=\frac{\Delta E}{\Delta t}

    Instantaneous mechanical power

    P=F⃗⋅v⃗=Fvcos⁡θP=\vec F\cdot\vec v=Fv\cos\theta

    Parallel force form

    P=F∥vP=F_{\parallel}v

    Energy efficiency

    η=EusefulEinput\eta=\frac{E_{\mathrm{useful}}}{E_{\mathrm{input}}}

    Power efficiency

    η=PusefulPinput\eta=\frac{P_{\mathrm{useful}}}{P_{\mathrm{input}}}

    Percentage efficiency

    η%=100η\eta_{\%}=100\eta

    Overall efficiency of a simple useful-output cascade

    ηoverall=η1η2η3⋯\eta_{\mathrm{overall}}=\eta_1\eta_2\eta_3\cdots

    Gravitational power of a mass flow

    Pg=m˙ghP_g=\dot m gh

    Mechanical-to-thermal balance with no external energy transfer

    Emech,i=Emech,f+ΔEthE_{\mathrm{mech},i}=E_{\mathrm{mech},f}+\Delta E_{\mathrm{th}}

    Spring constant from a graph

    k=ΔFΔxk=\frac{\Delta F}{\Delta x}

    Elastic work from graph area

    W=12Fx=12kx2W=\frac12Fx=\frac12kx^2

    Useful climbing power

    P=mgΔhΔtP=\frac{mg\Delta h}{\Delta t}
    Topic A.4Not started

    Rigid body mechanics

    Rigid body mechanics is an HL-only extension from linear motion to rotation. Torque plays a role analogous to force, moment of inertia plays a role analogous to mass, and angular momentum provides a rotational conservation law.

    420 min estimated

    Topic A.4 progress0%
    Learning objectives
    • Calculate torque from force magnitude, lever arm and angle.
    • Apply rotational equilibrium by setting the net torque to zero.
    • Use angular displacement, angular velocity and angular acceleration.
    • Apply constant-angular-acceleration equations in rotational motion.
    • Understand moment of inertia as a measure that depends on both total mass and how that mass is distributed relative to the axis.
    • Use τ = Iα to connect resultant torque and angular acceleration.
    • Calculate angular momentum and apply conservation of angular momentum when external torque is negligible.
    • Relate torque acting over time to angular impulse.
    • Calculate rotational kinetic energy.
    • Analyse rolling without slipping as simultaneous translation and rotation.
    Key formulas

    Radian definition

    θ=sr\theta=\frac{s}{r}

    Average angular velocity

    ωav=ΔθΔt\omega_{\mathrm{av}}=\frac{\Delta\theta}{\Delta t}

    Average angular acceleration

    αav=ΔωΔt\alpha_{\mathrm{av}}=\frac{\Delta\omega}{\Delta t}

    Angular-to-linear relationships

    v=r∣ω∣,at=rα,ac=rω2v=r|\omega|,\qquad a_{\mathrm{t}}=r\alpha,\qquad a_{\mathrm{c}}=r\omega^2

    Angular velocity–time

    ω=ω0+αt\omega=\omega_0+\alpha t

    Angular displacement–time

    Δθ=ω0t+12αt2\Delta\theta=\omega_0t+\frac12\alpha t^2

    No-time equation

    ω2=ω02+2αΔθ\omega^2=\omega_0^2+2\alpha\Delta\theta

    Mean-angular-velocity equation

    Δθ=ω0+ω2t\Delta\theta=\frac{\omega_0+\omega}{2}t

    Torque about a chosen origin (vector extension)

    τ=r×F\boldsymbol{\tau}=\mathbf{r}\times\mathbf{F}

    Planar torque magnitude about the perpendicular axis

    τ=rFsin⁡ϕ=Fd⊥\tau=rF\sin\phi=Fd_\perp

    Torque of a couple

    τcouple=Fd\tau_{\mathrm{couple}}=Fd

    Translational equilibrium

    Fnet=0\mathbf F_{\mathrm{net}}=\mathbf{0}

    Rotational equilibrium

    τnet=0\tau_{\mathrm{net}}=0

    Centre of mass for discrete masses

    rCM=∑i=1nmiri∑i=1nmi\mathbf r_{\mathrm{CM}}=\frac{\sum\limits_{i=1}^{n} m_i\mathbf r_i}{\sum\limits_{i=1}^{n} m_i}

    Discrete masses

    I=∑i=1nmiri2I=\sum\limits_{i=1}^{n} m_ir_i^2

    Continuous mass distribution

    I=∫r2 dmI=\int r^2\,dm

    Parallel-axis theorem

    I=ICM+Md2I=I_{\mathrm{CM}}+Md^2

    Thin uniform ring or hoop about its central symmetry axis

    I=MR2I=MR^2

    Uniform solid disk or cylinder about its central symmetry axis

    I=12MR2I=\frac12MR^2

    Uniform thin rod about a perpendicular axis through its centre

    I=112ML2I=\frac1{12}ML^2

    Uniform thin rod about a perpendicular axis through one end

    I=13ML2I=\frac13ML^2

    Uniform solid sphere about an axis through its centre

    I=25MR2I=\frac25MR^2

    Rotational Newton's second law

    τnet=Iα\tau_{\mathrm{net}}=I\alpha

    Net external angular impulse about a fixed axis

    Jangular,net=∫τext,net dt=ΔLJ_{\mathrm{angular,net}}=\int\tau_{\mathrm{ext,net}}\,dt=\Delta L

    Constant net-torque angular impulse

    τext,netΔt=ΔL\tau_{\mathrm{ext,net}}\Delta t=\Delta L

    Particle angular momentum

    L=r×p\mathbf L=\mathbf r\times\mathbf p

    Angular-momentum component about a fixed axis

    L=IωL=I\omega

    Torque and angular momentum about a fixed inertial origin

    τext,net=dLdt\boldsymbol\tau_{\mathrm{ext,net}}=\frac{d\mathbf L}{dt}

    Angular-momentum conservation

    Lbefore=LafterL_{\mathrm{before}}=L_{\mathrm{after}}

    Work by constant torque

    W=τΔθW=\tau\Delta\theta

    Work by variable torque

    W=∫θiθfτ dθW=\int_{\theta_i}^{\theta_f}\tau\,d\theta

    Fixed-axis rotational kinetic energy

    Krot=12Iω2=L22IK_{\mathrm{rot}}=\frac12I\omega^2=\frac{L^2}{2I}

    Rotational power

    P=τωP=\tau\omega

    No-slip speed constraint

    vCM=R∣ω∣v_{\mathrm{CM}}=R|\omega|

    No-slip acceleration constraint

    aCM=αRa_{\mathrm{CM}}=\alpha R

    Total rolling kinetic energy

    K=12MvCM2+12ICMω2K=\frac12Mv_{\mathrm{CM}}^2+\frac12I_{\mathrm{CM}}\omega^2

    Free gravity-driven rolling down a fixed incline (no slip or losses)

    a=gsin⁡β1+ICM(MR2)a=\frac{g\sin\beta}{1+\frac{I_{\mathrm{CM}}}{(MR^2)}}

    Coupled linear dynamics

    Fnet=maF_{\mathrm{net}}=ma

    Coupled rotational dynamics

    τnet=Iα\tau_{\mathrm{net}}=I\alpha

    No-slip coupling

    a=αRa=\alpha R
    Topic A.5Not started

    Galilean and special relativity

    This HL-only subtopic begins with classical relative motion and then shows why the invariance of the speed of light requires a new relationship between space and time. Students use Lorentz transformations and spacetime ideas quantitatively.

    480 min estimated

    Topic A.5 progress0%
    Learning objectives
    • Describe inertial reference frames and use Galilean transformations at low speeds.
    • Use classical relative velocity and recognize its limitations near the speed of light.
    • State and apply the two postulates of special relativity.
    • Calculate the Lorentz factor γ.
    • Use Lorentz transformations for position and time in one-dimensional motion.
    • Apply relativistic velocity addition.
    • Use the spacetime interval and distinguish proper time from coordinate time.
    • Calculate time dilation and length contraction.
    • Explain the relativity of simultaneity.
    • Interpret basic spacetime diagrams and relate their axes to relative speed.
    • Use high-speed particle observations such as atmospheric muons as evidence for relativistic effects.
    Key formulas

    Classical relative velocity

    vB/A=vB/S−vA/Sv_{\text{B/A}}=v_{\text{B/S}}-v_{\text{A/S}}

    Uniform frame motion

    xorigin of S′=vtx_{\mathrm{origin\ of\ }S'}=vt

    Galilean position transformation

    x′=x−vt,t′=tx'=x-vt,\qquad t'=t

    Inverse Galilean transformation

    x=x′+vt,t=t′x=x'+vt,\qquad t=t'

    Galilean velocity transformation

    ux′=ux−vu'_x=u_x-v

    Acceleration invariance classically

    ax′=axa'_x=a_x

    Vacuum light speed

    c≈2.998×108 m s−1c\approx2.998\times10^8\ \mathrm{m\,s^{-1}}

    Stationary light-clock path

    L=cΔτ2L=\frac{c\Delta\tau}{2}

    Moving light-clock geometry

    (cΔt2)2=L2+(vΔt2)2\left(\frac{c\Delta t}{2}\right)^2=L^2+\left(\frac{v\Delta t}{2}\right)^2

    Dimensionless speed

    β=vc\beta=\frac{v}{c}

    Lorentz factor

    γ=11−β2=11−v2c2\gamma=\frac{1}{\sqrt{1-\beta^2}}=\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}

    Speed from Lorentz factor

    vc=1−1γ2\frac{v}{c}=\sqrt{1-\frac{1}{\gamma^2}}

    Lorentz position transformation

    x′=γ(x−vt)x'=\gamma(x-vt)

    Lorentz time transformation

    t′=γ(t−vxc2)t'=\gamma\left(t-\frac{vx}{c^2}\right)

    Transverse coordinates

    y′=y,z′=zy'=y,\qquad z'=z

    Inverse position transformation

    x=γ(x′+vt′)x=\gamma(x'+vt')

    Inverse time transformation

    t=γ(t′+vx′c2)t=\gamma\left(t'+\frac{vx'}{c^2}\right)

    Forward collinear velocity addition

    u=u′+v1+u′vc2u=\frac{u'+v}{1+\frac{u'v}{c^2}}

    Inverse velocity transformation

    u′=u−v1−uvc2u'=\frac{u-v}{1-\frac{uv}{c^2}}

    Dimensionless velocity form

    uc=u′c+vc1+(u′c)(vc)\frac{u}{c}=\frac{\frac{u'}{c}+\frac{v}{c}}{1+(\frac{u'}{c})(\frac{v}{c})}

    One-dimensional spacetime interval

    Δs2=c2Δt2−Δx2\Delta s^2=c^2\Delta t^2-\Delta x^2

    Three-dimensional spacetime interval

    Δs2=c2Δt2−Δx2−Δy2−Δz2\Delta s^2=c^2\Delta t^2-\Delta x^2-\Delta y^2-\Delta z^2

    Inertial-clock proper time from a one-dimensional interval

    Δτ=Δt2−Δx2c2\Delta\tau=\sqrt{\Delta t^2-\frac{\Delta x^2}{c^2}}

    Interval classification

    Δs2>0 timelike,Δs2=0 lightlike,Δs2<0 spacelike\Delta s^2>0\ \mathrm{timelike},\quad \Delta s^2=0\ \mathrm{lightlike},\quad \Delta s^2<0\ \mathrm{spacelike}

    Time dilation for uniform relative motion

    Δt=γΔτ\Delta t=\gamma\Delta\tau

    Uniform-motion proper time

    Δτ=Δtγ\Delta\tau=\frac{\Delta t}{\gamma}

    Travel distance in a frame

    d=vΔtd=v\Delta t

    Length contraction

    L=L0γ=L01−v2c2L=\frac{L_0}{\gamma}=L_0\sqrt{1-\frac{v^2}{c^2}}

    Proper length from contracted length

    L0=γLL_0=\gamma L

    Simultaneous endpoint condition

    Δtmeasuring frame=0\Delta t_{\mathrm{measuring\ frame}}=0

    Time-separation transformation

    Δt′=γ(Δt−vΔxc2)\Delta t'=\gamma\left(\Delta t-\frac{v\Delta x}{c^2}\right)

    Simultaneous in S

    Δt=0⟹Δt′=−γvΔxc2\Delta t=0\quad\Longrightarrow\quad\Delta t'=-\gamma\frac{v\Delta x}{c^2}

    Einstein synchronization condition

    tB=tsend+treturn2t_B=\frac{t_{\mathrm{send}}+t_{\mathrm{return}}}{2}

    Light-ray worldlines through the origin

    x=±ctx=\pm ct

    Constant-velocity worldline and angle to the time axis

    x=x0+vt=x0+vc(ct),tan⁡θ=∣v∣cx=x_0+vt=x_0+\frac{v}{c}(ct),\qquad \tan\theta=\frac{|v|}{c}

    Moving time axis

    x=vtx=vt

    Moving space axis

    ct=vcxct=\frac{v}{c}x

    Causal speed condition

    ∣ΔxΔt∣≤c\left|\frac{\Delta x}{\Delta t}\right|\le c

    Core relativity chain

    β=vc ⟹ γ=11−β2\beta=\frac vc\ \Longrightarrow\ \gamma=\frac1{\sqrt{1-\beta^2}}

    One-dimensional inertial-clock proper-time check

    v=ΔxΔt,Δτ=Δtγ=Δt2−Δx2c2v=\frac{\Delta x}{\Delta t},\qquad \Delta\tau=\frac{\Delta t}{\gamma}=\sqrt{\Delta t^2-\frac{\Delta x^2}{c^2}}

    Low-speed consistency

    v≪c⟹γ≈1v\ll c\quad\Longrightarrow\quad\gamma\approx1
  2. Unit 2
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    The Particulate Nature of Matter

    Theme B connects microscopic particle models with macroscopic thermal behaviour, energy balance, gases, thermodynamic processes and electric circuits. At HL, thermodynamics formalizes heat, work, internal energy and entropy.

    32 hours estimated ·5 topics

    Unit 2 progress0%
  3. Unit 3
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    Wave Behaviour

    Theme C moves from oscillation to wave propagation, interference, diffraction, standing waves, resonance and Doppler shifts. Higher Level adds a fully quantitative treatment of SHM, diffraction patterns and moving-source/observer Doppler effects.

    29 hours estimated ·5 topics

    Unit 3 progress0%
  4. Unit 4
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    Fields

    Theme D develops gravitational, electric and magnetic field models and then studies charged-particle motion and electromagnetic induction. Higher Level introduces potential-energy and potential-field descriptions as well as induction.

    38 hours estimated ·4 topics

    Unit 4 progress0%
  5. Unit 5
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    Nuclear and Quantum Physics

    Theme E follows the development of atomic and nuclear models, then extends into wave–particle duality, radioactive decay, fission, fusion and stellar physics. The HL-only quantum subtopic is one of the most conceptually distinctive parts of the course.

    39 hours estimated ·5 topics

    Unit 5 progress0%