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Mathematics AI · HL · Unit 1: Number and Algebra

Unit 1Topic 1.10Key Concepts66 min read

Expressions with rational exponents

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Meaning of rational and fractional exponents

A rational exponent is an exponent that can be written as a fraction mn\frac{m}{n}, where m∈Zm\in\mathbb Z, n∈Nn\in\mathbb N, and n>0n>0. The denominator tells us which root to take and the numerator tells us which power to apply.

For a positive real base aa, the definition is amn=amn=(an)ma^{\frac{m}{n}}=\sqrt[n]{a^m}=(\sqrt[n]{a})^m. Both forms are equivalent, but taking the root first often keeps numbers smaller and makes mental calculation easier.

A negative rational exponent means reciprocal, exactly as it does for integer exponents: a−mn=1amna^{\frac{-m}{n}}=\frac{1}{a^{\frac{m}{n}}}. It does not make the value negative.

Real-number domain conditions matter. An even root requires a non-negative radicand, while an odd root can accept a negative radicand. For reliable AI HL algebra, use positive bases unless a question explicitly requires analysis of a negative base.

Key terms

Rational exponent
An exponent of the form mn\frac{m}{n}, where mm and nn are integers and n>0n>0.
Index
The root number nn in an\sqrt[n]{a}; it becomes the denominator of the rational exponent.
Radicand
The expression inside a radical sign.
Reciprocal
The multiplicative inverse 1x\frac{1}{x}; a negative exponent creates a reciprocal.

Worked examples

Interpret a fractional exponent

Evaluate 272327^{\frac{2}{3}}.

  1. 1The denominator 3 means take a cube root.
  2. 2273=3\sqrt[3]{27}=3.
  3. 3The numerator 2 means square the result: 32=93^2=9.

Answer: 2723=927^{\frac{2}{3}}=9.

Use a negative rational exponent

Evaluate 16−3416^{\frac{-3}{4}}.

  1. 1The negative sign means take the reciprocal.
  2. 21614=216^{\frac{1}{4}}=2, so 1634=23=816^{\frac{3}{4}}=2^3=8.
  3. 3Take the reciprocal: 16−34=1816^{\frac{-3}{4}}=\frac{1}{8}.

Answer: 18\frac18.

Check the real domain

Compare (−32)25(-32)^{\frac{2}{5}} and (−16)14(-16)^{\frac{1}{4}} over the real numbers.

  1. 1A fifth root is an odd root, so −325=−2\sqrt[5]{-32}=-2 and (−2)2=4(-2)^2=4.
  2. 2A fourth root is an even root, and no real number has fourth power −16-16.

Answer: (−32)25=4(-32)^{\frac{2}{5}}=4, while (−16)14(-16)^{\frac{1}{4}} is not real.

Rules and formulas

Rational exponent definition

amn=amn=(an)ma^{\frac{m}{n}}=\sqrt[n]{a^m}=(\sqrt[n]{a})^m

Negative rational exponent

a−mn=1amna^{\frac{-m}{n}}=\frac{1}{a^{\frac{m}{n}}}

Special root form

a1n=ana^{\frac{1}{n}}=\sqrt[n]{a}

Converting between radicals and rational exponents

Radical notation and rational-exponent notation express the same operation. Converting to exponent notation is especially useful when multiplying, dividing, differentiating later in the course, or entering expressions into a GDC.

For x>0x>0, integer mm and positive integer nn, use xmn=xmn\sqrt[n]{x^m}=x^{\frac{m}{n}}. A coefficient outside the radical stays outside. Splitting a radical of a product into radicals of its factors is safe when those factors are positive; check domains separately for zero or negative factors.

When simplifying even roots of variable squares, remember absolute value: x2=∣x∣\sqrt{x^2}=|x|. If a question states x>0x>0, then ∣x∣=x|x|=x; without that condition, removing the absolute value is not justified.

Key terms

Radical form
Notation using a root symbol, such as x23\sqrt[3]{x^2}.
Exponent form
Equivalent power notation, such as x23x^{\frac{2}{3}}.
Absolute value
The non-negative magnitude ∣x∣|x|, required because the principal square root is never negative.

Worked examples

Radical to exponent form

Write x35\sqrt[5]{x^3} using a rational exponent.

  1. 1The index 5 becomes the denominator.
  2. 2The power 3 becomes the numerator.

Answer: x35=x35\sqrt[5]{x^3}=x^{\frac{3}{5}}.

Exponent to radical form

Write y74y^{\frac{7}{4}} in radical form.

  1. 1The denominator 4 gives a fourth root.
  2. 2The numerator 7 gives the power.

Answer: y74=y74=(y4)7y^{\frac{7}{4}}=\sqrt[4]{y^7}=(\sqrt[4]{y})^7.

Simplify a radical exactly

Simplify 54x73\sqrt[3]{54x^7}.

  1. 1Factor perfect cubes: 54x7=27x6(2x)54x^7=27x^6(2x).
  2. 2Take the cube root of 27x627x^6: 27x63=3x2\sqrt[3]{27x^6}=3x^2.
  3. 3Leave the remaining factor inside the cube root.

Answer: 3x22x33x^2\sqrt[3]{2x}.

Rules and formulas

Radical–exponent conversion

xmn=xmn,x>0, m∈Z, n∈Z>0\sqrt[n]{x^m}=x^{\frac{m}{n}},\qquad x>0,\ m\in\mathbb Z,\ n\in\mathbb Z_{>0}

Principal square root

x2=∣x∣\sqrt{x^2}=|x|

Odd root of a power

x2k+12k+1=x\sqrt[2k+1]{x^{2k+1}}=x

Laws of exponents with rational powers

For positive bases, the usual exponent laws hold for rational exponents: combine powers of the same base by adding or subtracting exponents, and multiply exponents for a power of a power. For negative bases, merely having real, defined expressions is not enough to guarantee every exponent law; check the domain and principal-root convention separately.

When multiplying powers with the same base, add exponents. When dividing, subtract exponents. When raising a power to another power, multiply exponents.

A power distributes over a product or quotient, but it does not distribute over a sum: (x+y)r≠xr+yr(x+y)^r\ne x^r+y^r in general.

Zero deserves special care: 0r0^r is defined for positive rr, but 000^0 and 0r0^r for negative rr are undefined.

Key terms

Product law
Same-base powers multiply by adding their exponents.
Quotient law
Same-base powers divide by subtracting their exponents.
Power of a power
Raising ara^r to ss multiplies the exponents.
Domain restriction
A condition required to keep every algebraic expression defined in the chosen number system.

Worked examples

Multiply rational powers

Simplify x23x56x^{\frac{2}{3}}x^{\frac{5}{6}} for x>0x>0.

  1. 1Use a common denominator: 23=46\frac{2}{3}=\frac{4}{6}.
  2. 2Add exponents: 46+56=96=32\frac{4}{6}+\frac{5}{6}=\frac{9}{6}=\frac{3}{2}.

Answer: x32x^{\frac{3}{2}}.

Divide rational powers

Simplify a74a12\frac{a^{\frac{7}{4}}}{a^{\frac{1}{2}}} for a>0a>0.

  1. 1Rewrite 12\frac{1}{2} as 24\frac{2}{4}.
  2. 2Subtract exponents: 74−24=54\frac{7}{4}-\frac{2}{4}=\frac{5}{4}.

Answer: a54a^{\frac{5}{4}}.

Power of a power

Simplify (p35)109(p^{\frac{3}{5}})^{\frac{10}{9}} for p>0p>0.

  1. 1Multiply the exponents: (35)(109)=3045=23(\frac{3}{5})(\frac{10}{9})=\frac{30}{45}=\frac{2}{3}.

Answer: p23p^{\frac{2}{3}}.

Rules and formulas

Product law

aras=ar+sa^r a^s=a^{r+s}

Quotient law

aras=ar−s\frac{a^r}{a^s}=a^{r-s}

Power of a power

(ar)s=ars(a^r)^s=a^{rs}

Power of a product

(ab)r=arbr(ab)^r=a^r b^r

Power of a quotient

(ab)r=arbr\left(\frac ab\right)^r=\frac{a^r}{b^r}

Simplifying expressions involving rational exponents

A strong simplification keeps values exact, combines like bases, removes negative exponents when requested, and states domain conditions when they matter.

Work in a consistent notation. Convert radicals to powers before using exponent laws, then convert back to radical form only if it makes the final answer clearer.

Factor coefficients into perfect powers. For example, recognizing 81=3481=3^4 makes fourth roots immediate.

Key terms

Exact value
A value written without premature decimal approximation, such as 323\sqrt2 or 2532^{\frac{5}{3}}.
Positive exponent form
A final form with negative exponents rewritten as reciprocals.
Like bases
Powers sharing the same base, which can be combined using exponent laws.

Worked examples

Combine several powers

Simplify x32x−14x12\frac{x^{\frac{3}{2}}x^{\frac{-1}{4}}}{x^{\frac{1}{2}}} for x>0x>0.

  1. 1Add numerator exponents and subtract the denominator exponent.
  2. 232−14−12=64−14−24=34\frac{3}{2}-\frac{1}{4}-\frac{1}{2}=\frac{6}{4}-\frac{1}{4}-\frac{2}{4}=\frac{3}{4}.

Answer: x34x^{\frac{3}{4}}.

Simplify a numerical expression

Evaluate 8134⋅81381^{\frac{3}{4}}\cdot 8^{\frac{1}{3}}.

  1. 18114=381^{\frac{1}{4}}=3, so 8134=33=2781^{\frac{3}{4}}=3^3=27.
  2. 2813=28^{\frac{1}{3}}=2.
  3. 3Multiply: 27⋅2=5427\cdot2=54.

Answer: 5454.

Remove a negative exponent

Simplify (16x−8)34(16x^{-8})^{\frac{3}{4}} for x>0x>0.

  1. 1Apply the power to each factor.
  2. 21634=816^{\frac{3}{4}}=8 and (x−8)34=x−6(x^{-8})^{\frac{3}{4}}=x^{-6}.
  3. 3Rewrite with a positive exponent.

Answer: 8x6\frac{8}{x^6}.

Rules and formulas

Negative exponent conversion

x−r=1xrx^{-r}=\frac{1}{x^r}

Common-denominator strategy

xpqxrs=x(ps+rq)(qs)x^{\frac{p}{q}}x^{\frac{r}{s}}=x^{\frac{(ps+rq)}{(qs)}}

Exact before decimal

amn=amn\sqrt[n]{a^m}=a^{\frac{m}{n}}

Real domains, negative bases, and principal roots

For a>0a>0, every real rational power amna^{\frac{m}{n}} is defined and the exponent laws behave consistently. When variables occur, a positive-base condition such as x>0x>0 is often stated so that all transformations remain valid.

For a negative real base, first reduce mn\frac{m}{n} to lowest terms. A real value can exist when the reduced denominator nn is odd: for example, (−32)25=(−325)2=4(-32)^{\frac{2}{5}}=(\sqrt[5]{-32})^2=4. If the reduced denominator is even, the value is not real.

The principal even root is non-negative. Therefore x2=∣x∣\sqrt{x^2}=|x|, not always xx, and (x2)12=∣x∣(x^2)^{\frac{1}{2}}=|x|. This distinction becomes important when solving equations and simplifying expressions without an assumption such as x≥0x\ge0.

Zero is allowed only when the resulting exponent is positive. Expressions such as 0−120^{\frac{-1}{2}} are undefined because they require division by zero, while 023=00^{\frac{2}{3}}=0.

Key terms

Principal root
The standard non-negative value selected by an even-root symbol.
Reduced exponent
A rational exponent mn\frac{m}{n} written with gcd⁡(m,n)=1\gcd(m,n)=1 and n>0n>0.
Real domain
The inputs for which an expression has a real-number value.
Absolute value
The non-negative magnitude ∣x∣|x|, needed because x2=∣x∣\sqrt{x^2}=|x|.

Worked examples

Odd denominator with a negative base

Evaluate (−64)23(-64)^{\frac{2}{3}} over the real numbers.

  1. 1The reduced denominator is 3, so take a real cube root.
  2. 2−643=−4\sqrt[3]{-64}=-4.
  3. 3Square the result: (−4)2=16(-4)^2=16.

Answer: (−64)23=16(-64)^{\frac{2}{3}}=16.

Even denominator with a negative base

Determine whether (−16)34(-16)^{\frac{3}{4}} is real.

  1. 1The exponent is already reduced and its denominator is even.
  2. 2The expression requires the real fourth root of −16-16, which does not exist.

Answer: The expression is not real.

Simplify an even root correctly

Simplify (9x2)12(9x^2)^{\frac{1}{2}} for real xx.

  1. 1(9x2)12=9x2=3x2(9x^2)^{\frac{1}{2}}=\sqrt{9x^2}=3\sqrt{x^2}.
  2. 2Use x2=∣x∣\sqrt{x^2}=|x|.

Answer: 3∣x∣3|x|.

Rules and formulas

Negative base with odd reduced denominator

(−a)mn=(−an)m(n odd)(-a)^{\frac{m}{n}}=\left(\sqrt[n]{-a}\right)^m\quad(n\text{ odd})

Principal square root

(x2)12=x2=∣x∣(x^2)^{\frac{1}{2}}=\sqrt{x^2}=|x|

Zero restriction

0r is defined for r>0 and undefined for r<00^r\text{ is defined for }r>0\text{ and undefined for }r<0

Solving equations involving rational exponents

Begin by stating the real domain. Then isolate the rational-power expression and choose a transformation that preserves all possible solutions. Finish by checking every candidate in the original equation.

If xmn=kx^{\frac{m}{n}}=k with x≥0x\ge0, raising both sides to nm\frac{n}{m} may solve the equation directly. When an even power is present after taking an odd root, remember both signs: u2=ku^2=k gives u=±ku=\pm\sqrt{k}.

For equations containing several related fractional powers, substitute a simpler variable. For example, if both x12x^{\frac{1}{2}} and x14x^{\frac{1}{4}} appear, set u=x14u=x^{\frac{1}{4}}, so x12=u2x^{\frac{1}{2}}=u^2 and u≥0u\ge0.

Squaring or raising both sides to an even power can introduce extraneous candidates. A GDC is useful for locating or confirming solutions, but a graph window must cover the entire stated domain.

Key terms

Substitution
Replacing a repeated fractional power with a simpler variable to form a familiar equation.
Extraneous solution
A candidate created by algebra that fails the original equation or its domain.
Equivalent equation
An equation with exactly the same solution set as the original equation.
Candidate
A potential solution that must still be checked in the original equation.

Worked examples

Solve a direct rational-power equation

Solve x32=64x^{\frac{3}{2}}=64 over the reals.

  1. 1The square-root interpretation requires x≥0x\ge0.
  2. 2Raise both sides to 23\frac{2}{3}: x=6423x=64^{\frac{2}{3}}.
  3. 3643=4\sqrt[3]{64}=4, so x=42=16x=4^2=16.

Answer: x=16x=16.

Keep both branches

Solve (x−1)23=9(x-1)^{\frac{2}{3}}=9.

  1. 1Let u=(x−1)13u=(x-1)^{\frac{1}{3}}. Then u2=9u^2=9.
  2. 2Therefore u=3u=3 or u=−3u=-3.
  3. 3Cube each relation: x−1=27x-1=27 or x−1=−27x-1=-27.
  4. 4Check both values in the original equation.

Answer: x=28x=28 or x=−26x=-26.

Use a fractional-power substitution

Solve x12+x14−6=0x^{\frac{1}{2}}+x^{\frac{1}{4}}-6=0.

  1. 1The real domain is x≥0x\ge0. Let u=x14u=x^{\frac{1}{4}}, so u≥0u\ge0.
  2. 2Then u2+u−6=0=(u+3)(u−2)u^2+u-6=0=(u+3)(u-2).
  3. 3Reject u=−3u=-3 because u≥0u\ge0; use u=2u=2.
  4. 4Since x14=2x^{\frac{1}{4}}=2, x=16x=16.

Answer: x=16x=16.

Solve a negative-power equation

Solve x−12=14x^{\frac{-1}{2}}=\frac{1}{4}.

  1. 1The domain is x>0x>0. Rewrite as 1x=14\frac{1}{\sqrt{x}}=\frac{1}{4}.
  2. 2Therefore x=4\sqrt{x}=4, so x=16x=16.
  3. 3Substitution confirms the value.

Answer: x=16x=16.

Rules and formulas

Direct positive-domain pattern

xmn=k⟹x=knmx^{\frac{m}{n}}=k\quad\Longrightarrow\quad x=k^{\frac{n}{m}}

Useful substitution

u=x1n⟹xmn=umu=x^{\frac{1}{n}}\quad\Longrightarrow\quad x^{\frac{m}{n}}=u^m

Two-branch warning

u2=k⟹u=±ku^2=k\quad\Longrightarrow\quad u=\pm\sqrt{k}

Exact and approximate values

An exact value preserves the full mathematical quantity using integers, fractions, radicals, or powers. A decimal from a calculator is usually approximate and should be marked with an approximation sign.

Simplify exactly before approximating. Factor out perfect powers, take exact roots when possible, and retain the exact form during later calculations to avoid accumulated rounding error.

When the question requests a decimal, use guard digits and round once to the stated number of decimal places or significant figures. Include units and apply any contextual requirement such as a whole-number count.

Key terms

Exact value
A form such as 24324\sqrt3 that represents the value without rounding.
Approximation
A rounded numerical value written using an appropriate degree of accuracy.
Guard digits
Extra unrounded calculator digits retained until the final step.

Worked examples

Give exact and approximate forms

Evaluate 123212^{\frac{3}{2}} exactly and to three significant figures.

  1. 11232=121212^{\frac{3}{2}}=12\sqrt{12}.
  2. 2Since 12=23\sqrt{12}=2\sqrt3, the exact value is 24324\sqrt3.
  3. 3A GDC gives 41.5692…41.5692\ldots.

Answer: Exact: 24324\sqrt3. Approximate: 41.641.6 to three significant figures.

Simplify before approximating

Express 502350^{\frac{2}{3}} in a simplified radical form and as a decimal.

  1. 15023=5023=2500350^{\frac{2}{3}}=\sqrt[3]{50^2}=\sqrt[3]{2500}.
  2. 2Factor 2500=125×202500=125\times20.
  3. 3Thus 25003=5203≈13.5721\sqrt[3]{2500}=5\sqrt[3]{20}\approx13.5721.

Answer: 5203≈13.65\sqrt[3]{20}\approx13.6 to three significant figures.

Recognize an exact reciprocal

Evaluate 32−3532^{\frac{-3}{5}}.

  1. 13215=232^{\frac{1}{5}}=2, so 3235=23=832^{\frac{3}{5}}=2^3=8.
  2. 2The negative exponent takes the reciprocal.

Answer: 18\frac18.

Rules and formulas

Approximation notation

exact value≈rounded decimal\text{exact value}\approx\text{rounded decimal}

Factor a perfect nth power

cndn=cdn(c≥0 if n is even)\sqrt[n]{c^n d}=c\sqrt[n]{d}\quad(c\ge0\text{ if }n\text{ is even})

Power-model and scaling applications

Rational exponents appear naturally in power models y=Axpy=Ax^p. The exponent describes how the output responds to a multiplicative change in the input. For example, if p=23p=\frac{2}{3}, multiplying xx by kk multiplies yy by k23k^{\frac{2}{3}}.

Geometry provides common examples: the side length of a cube is the cube root of its volume, and surface area scales with volume to the power two-thirds for similar solids.

Scientific models may use fractional or negative powers to describe rates, metabolic relationships, intensity, or inverse scaling. State the practical domain—often positive measurements—even when the algebraic expression has a wider real domain.

A model prediction should include units, appropriate rounding, and a comment on assumptions. Extrapolating a power relationship far beyond the observed data may be unreliable.

Key terms

Power model
A relationship of the form y=Axpy=Ax^p.
Scale factor
A multiplier applied to a dimension or quantity.
Allometric model
A power model relating biological measurements such as mass and metabolic rate.
Practical domain
The input values meaningful in the context, such as positive length, mass, or time.

Worked examples

Recover a cube dimension

A cube has volume 2744 cm32744\text{ cm}^3. Find its side length.

  1. 1If the side is ss, then s3=2744s^3=2744.
  2. 2Thus s=274413=14s=2744^{\frac{1}{3}}=14.

Answer: 14 cm14\text{ cm}.

Use an allometric model

A model is B=0.12m34B=0.12m^{\frac{3}{4}}, where mm is mass in kilograms. Estimate BB when m=80m=80.

  1. 1Substitute m=80m=80: B=0.12(80)34B=0.12(80)^{\frac{3}{4}}.
  2. 2Use full calculator precision before rounding.

Answer: B≈3.21B\approx3.21 model units.

Apply a scaling exponent

A similar solid has surface area 250 cm2250\text{ cm}^2. Its volume is multiplied by 1.61.6. Estimate the new surface area.

  1. 1For similar solids, surface area scales as volume to the power 23\frac{2}{3}.
  2. 2New area =250(1.6)23≈341.995=250(1.6)^{\frac{2}{3}}\approx341.995.

Answer: Approximately 342 cm2342\text{ cm}^2.

Rules and formulas

Power model

y=Axpy=Ax^p
AA
constant of proportionality
pp
power or scaling exponent

Scaling response

x↦kx⟹y↦kpyx\mapsto kx\quad\Longrightarrow\quad y\mapsto k^p y

Cube side from volume

s=V13s=V^{\frac{1}{3}}

Calculator and GDC methods

Enter a fractional exponent with brackets: type a(mn)a^{(\frac{m}{n})}, not amn\frac{a^m}{n}. Use the negative-number key inside the exponent when evaluating a−mna^{\frac{-m}{n}}.

For exact perfect powers, work mentally or algebraically before using a decimal. A GDC can confirm the result, but a decimal display does not replace exact working when exact form is required.

Many calculators use the principal complex interpretation or return an error for negative bases with fractional exponents. For a real odd root, use the nth-root function or take the odd root first, then apply the numerator power.

To solve an equation, graph each side or use a numerical solver with the correct domain. Scan the domain and use multiple starting values if more than one solution may exist. Record the equation and the relevant coordinate or numerical result.

Key terms

nth-root function
A calculator command that directly evaluates an nth root and can handle real odd roots of negative values.
Graph intersection
A point where two plotted expressions have the same input and output.
Numerical solver
A GDC tool that approximates a solution from an equation and starting value or interval.
Window
The displayed x- and y-ranges used when graphing functions.

Worked examples

Enter a negative fractional exponent

Evaluate 32−3532^{\frac{-3}{5}} on a GDC.

  1. 1Enter 32(−35)32^{(\frac{-3}{5})} with the entire exponent bracketed.
  2. 2The display gives 0.125.
  3. 3Recognize the exact value 0.125=180.125=\frac{1}{8}.

Answer: 18\frac18.

Evaluate a negative base safely

Evaluate (−32)25(-32)^{\frac{2}{5}} as a real number.

  1. 1Do not rely on a direct fractional-power entry if the calculator reports an error.
  2. 2Use the fifth-root command: −325=−2\sqrt[5]{-32}=-2.
  3. 3Square: (−2)2=4(-2)^2=4.

Answer: 44.

Solve numerically

Use a GDC to solve x32+x=20x^{\frac{3}{2}}+x=20.

  1. 1The real domain is x≥0x\ge0. Graph y1=x32+xy_1=x^{\frac{3}{2}}+x and y2=20y_2=20.
  2. 2Use the intersection command in a window containing the crossing.
  3. 3Substitute the result to check both sides.

Answer: x≈5.850x\approx5.850.

Rules and formulas

Safe calculator entry

amn  ⟶  a(mn)a^{\frac{m}{n}}\;\longrightarrow\;a^{(\frac{m}{n})}

Real negative-base evaluation

(−a)mn=(−an)m(n odd)(-a)^{\frac{m}{n}}=\left(\sqrt[n]{-a}\right)^m\quad(n\text{ odd})

IB AI HL-style practice with worked solutions

These questions progress from notation and exact simplification to domain-sensitive equations, modelling, and technology. Keep exponent fractions exact and state assumptions such as positivity when they justify a law.

In exam responses, show the conversion or exponent law used, preserve all algebraic branches, check candidates, and interpret application answers with units and appropriate accuracy.

Key terms

Method mark
Credit earned for a valid mathematical method even if a later arithmetic error occurs.
Exact form
An unrounded representation using fractions, powers, or radicals.
Admissible solution
A solution satisfying the original equation, real domain, and contextual restrictions.

Worked examples

Practice 1 · Interpret a rational exponent

Evaluate 642364^{\frac{2}{3}}.

  1. 1Take the cube root first: 6413=464^{\frac{1}{3}}=4.
  2. 2Square: 42=164^2=16.

Answer: 1616.

Practice 2 · Negative rational exponent

Evaluate 32−3532^{\frac{-3}{5}}.

  1. 13215=232^{\frac{1}{5}}=2, so 3235=832^{\frac{3}{5}}=8.
  2. 2Take the reciprocal.

Answer: 18\frac18.

Practice 3 · Convert notation

Write x47\sqrt[7]{x^4} using a rational exponent.

  1. 1The root index becomes the denominator and the power becomes the numerator.

Answer: x47x^{\frac{4}{7}}.

Practice 4 · Combine powers

Simplify x56x−14x13\frac{x^{\frac{5}{6}}x^{\frac{-1}{4}}}{x^{\frac{1}{3}}} for x>0x>0.

  1. 1Combine exponents: 56−14−13\frac{5}{6}-\frac{1}{4}-\frac{1}{3}.
  2. 2Using denominator 12 gives 1012−312−412=14\frac{10}{12}-\frac{3}{12}-\frac{4}{12}=\frac{1}{4}.

Answer: x14x^{\frac{1}{4}}.

Practice 5 · Power of a product

Simplify (81a8)34(81a^8)^{\frac{3}{4}} for a>0a>0.

  1. 18134=2781^{\frac{3}{4}}=27.
  2. 2(a8)34=a6(a^8)^{\frac{3}{4}}=a^6.

Answer: 27a627a^6.

Practice 6 · Direct equation

Solve x32=125x^{\frac{3}{2}}=125 over the reals.

  1. 1The domain is x≥0x\ge0.
  2. 2Raise to 23\frac{2}{3}: x=12523=25x=125^{\frac{2}{3}}=25.

Answer: x=25x=25.

Practice 7 · Two real branches

Solve x23=9x^{\frac{2}{3}}=9.

  1. 1Let u=x13u=x^{\frac{1}{3}}. Then u2=9u^2=9.
  2. 2So u=±3u=\pm3, and cubing gives x=±27x=\pm27.

Answer: x=−27x=-27 or x=27x=27.

Practice 8 · Fractional-power substitution

Solve x12+x14=12x^{\frac{1}{2}}+x^{\frac{1}{4}}=12.

  1. 1Let u=x14≥0u=x^{\frac{1}{4}}\ge0. Then u2+u−12=0u^2+u-12=0.
  2. 2(u+4)(u−3)=0(u+4)(u-3)=0, so u=3u=3.
  3. 3Thus x=34=81x=3^4=81.

Answer: x=81x=81.

Practice 9 · Negative-power equation

Solve x−12=15x^{\frac{-1}{2}}=\frac{1}{5}.

  1. 1Domain: x>0x>0. Rewrite as 1x=15\frac{1}{\sqrt{x}}=\frac{1}{5}.
  2. 2Hence x=5\sqrt{x}=5, so x=25x=25.

Answer: x=25x=25.

Practice 10 · Exact and approximate value

Express 502350^{\frac{2}{3}} exactly and to three significant figures.

  1. 15023=25003=125×203=520350^{\frac{2}{3}}=\sqrt[3]{2500}=\sqrt[3]{125\times20}=5\sqrt[3]{20}.
  2. 2Evaluate only after obtaining the exact form.

Answer: 5203≈13.65\sqrt[3]{20}\approx13.6.

Practice 11 · Scaling model

A surface area of 250 cm2250\text{ cm}^2 scales with volume to the power 23\frac{2}{3}. Find the new area when volume is multiplied by 1.61.6.

  1. 1Use the factor 1.6231.6^{\frac{2}{3}}.
  2. 2New area =250(1.6)23≈341.995=250(1.6)^{\frac{2}{3}}\approx341.995.

Answer: Approximately 342 cm2342\text{ cm}^2.

Practice 12 · Numerical solution

Use a GDC to solve x32+x=20x^{\frac{3}{2}}+x=20.

  1. 1Use domain x≥0x\ge0. Graph y1=x32+xy_1=x^{\frac{3}{2}}+x and y2=20y_2=20.
  2. 2Find the intersection and verify by substitution.

Answer: x≈5.850x\approx5.850.

Rules and formulas

Equation workflow

DOMAIN→SUBSTITUTE→SOLVE→CHECK\text{DOMAIN}\to\text{SUBSTITUTE}\to\text{SOLVE}\to\text{CHECK}

Scaling rule

y=Axp,x↦kx⇒y↦kpyy=Ax^p,\quad x\mapsto kx\Rightarrow y\mapsto k^py

Topic summary and cheat sheet

Use the denominator as the root, the numerator as the power, and a negative sign as a reciprocal. Check the real domain before applying any exponent law.

For equations, state the domain, use a substitution when powers share a common fractional unit, preserve both branches of even-power equations, and check every candidate.

In applications, interpret the power as a scaling relationship, retain exact values during working, and report the final approximation with units and sensible accuracy.

Key terms

Denominator
Gives the root index.
Numerator
Gives the power.
Negative sign
Creates a reciprocal.
Even root
Requires a non-negative radicand over the reals.

Worked examples

Rapid evaluation

Evaluate 81−1481^{\frac{-1}{4}}.

  1. 18114=381^{\frac{1}{4}}=3.
  2. 2Take the reciprocal.

Answer: 13\frac13.

Rapid domain check

State the real domain of (x−5)32(x-5)^{\frac{3}{2}}.

  1. 1The denominator 2 requires x−5≥0x-5\ge0.

Answer: x≥5x\ge5.

Rules and formulas

Rational exponent

amn=amn=(an)ma^{\frac{m}{n}}=\sqrt[n]{a^m}=(\sqrt[n]{a})^m

Negative rational exponent

a−mn=1amna^{\frac{-m}{n}}=\frac1{a^{\frac{m}{n}}}

Product law

aras=ar+sa^ra^s=a^{r+s}

Quotient law

aras=ar−s\frac{a^r}{a^s}=a^{r-s}

Power of a power

(ar)s=ars(a^r)^s=a^{rs}

Principal square root

x2=∣x∣\sqrt{x^2}=|x|

Topic summary

  • A rational exponent has the form mn\frac{m}{n}, with n>0n>0.
  • For a>0a>0, amn=amn=(an)ma^{\frac{m}{n}}=\sqrt[n]{a^m}=(\sqrt[n]{a})^m.
  • The denominator gives the root and the numerator gives the power.
  • A negative exponent means reciprocal: a−mn=1amna^{\frac{-m}{n}}=\frac{1}{a^{\frac{m}{n}}}.
  • For negative bases, reduce the exponent first; a real value may exist when the reduced denominator is odd.
  • Principal even roots are non-negative, so x2=∣x∣\sqrt{x^2}=|x|.
  • Multiply same-base powers by adding exponents and divide by subtracting exponents.
  • For a power of a power, multiply exponents: (ar)s=ars(a^r)^s=a^{rs}.
  • Powers distribute over products and quotients, not over sums or differences.
  • Keep exact powers or radicals during working and round only the requested final value.
  • For equations use DOMAIN → SUBSTITUTE → SOLVE → CHECK.
  • Even-power equations may create two branches; do not keep only the principal root.
  • In a power model y=Axpy=Ax^p, multiplying xx by kk multiplies yy by kpk^p.
  • Use brackets around a fractional exponent on a GDC and use an nth-root command for real odd roots of negative numbers.
  • Numerical solutions must include the entered equation, domain, appropriate rounding, and contextual interpretation.